[AP] lotus formula openview

Hello! I need to do this:

I have one frameset with 3 frames. And I need to open my views in one of this frames.
I need to use action buttons (on view action bar) to open views.

As i found in this forum, there is BIG problem to opening views in the same window. In my case - in the same frame!!!

The LS method uidb.OpenView("ViewFrame") don't work in this case! A LS error occurs: "unabled to use this method in this context".

So i tried to use Formula language:
1. I'v created agent

Triger: OnEvent (AgentListSelection)
Target: None.

Code:

@SetTargetFrame("ViewFrame")
@Command([OpenView]; "MyView")


2. For run agent i use action button with LS code.

Set db = ls.CurrentDatabase
Set agent = db.GetAgent("(OpenView)")
Call agent.Run() 

And again the same error occur: "@Function is not valid in this context"!!! @SetTargetFrame() and @Command([OpenView]) don't work in agent.

I tried to place the same code in view action button:
@SetTargetFrame("ViewFrame")
@Command([OpenView]; "MyView")

In this case this commands work! And view "MyView" opens in frame "ViewFrame"!!!

Of couse i could stop on it. But i need more LS code in action button!!! So i need to do that just using LS or agent!